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Snarty does my very simple Hw....


Doom103
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<Doom> Smarty

<@SmartRutter> yeah?

<Slyver> Be a ninja then.

<Doom> Want a math question

<@SmartRutter> uh idk

<Slyver> TRISEXUALS!!!

<Slyver> LAWL

<Doom> if the permimeter of a parallelogram is 132,...

<Javaman> 4!

<Doom> the longest possible lenght of a diagonal is less than ____

<Javaman> uh...

...... later on

<Doom> Let me finish the other problems and I'll bbl

<Slyver> ...

<@SmartRutter> like one question where i'd use calculus on would be like... someone has 200 ft of fencing to put around there farmland

<Slyver> *sigh*

<@SmartRutter> find the dimensions to make the most area

<@SmartRutter> and of course it'd be a rectangular shape

<@SmartRutter> so i'd label X and Y as two sides

<@SmartRutter> A = 200ft

<@SmartRutter> A = XY

<@SmartRutter> therefore XY = 200

<@SmartRutter> Y = 200/X

<@SmartRutter> A = XY

<@SmartRutter> subsitution

<@SmartRutter> wait no

<@SmartRutter> that wouldn't help

<@SmartRutter> ummm

<@SmartRutter> A'=X+Y

<@SmartRutter> (that'd be the derivative of the area)

<@SmartRutter> A'=X+200/X

<Doomer> We need a Doomest.

<@SmartRutter> i'd have to solve for when A' equals zero

<@SmartRutter> the reasoning is that derivative = slope, and a zero slope on a curve is a max or min value

<@SmartRutter> think of a parabola

<@SmartRutter> so 0=X+200/X

<@SmartRutter> wait...

<@SmartRutter> ok i got it now

<@SmartRutter> -200/X=X

<@SmartRutter> cross-multiply

<@SmartRutter> X^2=-200

<@SmartRutter> -X^2 = 200

<@SmartRutter> square root

<@SmartRutter> i forget whatever the sqrt of 200 is -_-

<@SmartRutter> roughly 14.1421

<Kiba> smarty be quiet!!!!!

<@SmartRutter> so back to finding Y...

<Kiba> its not school time!

<@SmartRutter> bah'

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