Créer une présentation
Télécharger la présentation

Télécharger la présentation
## Gain, Attenuation, Decibels

- - - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - - -

**Gain, Attenuation, Decibels**Chapter 1(part 2) EKT343 –Principle of Communication Engineering**Gain, Attenuation,and Decibels**• Most circuits in electronic communication are used to manipulate signals to produce a desired result. • All signal processing circuits involve: • Gain • Attenuation**output**Vout input Vin = AV = Gain, Attenuation,and Decibels Gain • Gain means amplification. It is the ratio of a circuit’s output to its input. Figure 2-1: An amplifier has gain.**Gain, Attenuation,and Decibels**• Most amplifiers are also power amplifiers, so the same procedure can be used to calculate power gain AP where Pin is the power input and Pout is the power output. Power gain (Ap)= Pout / Pin • Example: The power output of an amplifier is 6 watts (W). The power gain is 80. What is the input power? Ap= Pout / Pin therefore Pin = Pout / Ap Pin = 6 / 80 = 0.075 W = 75 mW**Gain, Attenuation,and Decibels**• An amplifier is cascaded when two or more stages are connected together. • The overall gain is the product of the individual circuit gains. • Example: Three cascaded amplifiers have power gains of 5, 2, and 17. The input power is 40 mW. What is the output power? Ap = A1×A2× A3 = 5 × 2 × 17 = 170 Ap= Pout / Pin therefore Pout = ApPin Pout = 170 (40 × 10-3) = 6.8W**Gain, Attenuation, and Decibels**Attenuation • Attenuation refers to a loss introduced by a circuit or component. If the output signal is lower in amplitude than the input, the circuit has loss or attenuation. • The letter A is used to represent attenuation • Attenuation A = output/input = Vout/Vin • Circuits that introduce attenuation have a gain that is less than 1. • With cascaded circuits, the total attenuation is the product of the individual attenuations.**Figure 2-3: A voltage divider introduces attenuation.**Gain, Attenuation,and Decibels**Figure 2-4: Total attenuation is the product of individual**attenuations of each cascaded circuit. Gain, Attenuation,and Decibels**Gain, Attenuation,and Decibels**Decibels • The decibel (dB) is a unit of measure used to express the gain or loss of a circuit. • The decibel was originally created to express hearing response. • A decibel is one-tenth of a bel. • When gain and attenuation are both converted into decibels, the overall gain or attenuation of a circuit can be computed by adding individual gains or attenuations, expressed in decibels.**Gain, Attenuation,and Decibels**Decibels: Decibel Calculations • Voltage Gain or Attenuation dB = 20 log Vout/ Vin • Current Gain or Attenuation dB = 20 log Iout/ Iin • Power Gain or Attenuation dB = 10 log Pout/ Pin**Gain, Attenuation,and Decibels**Decibels: Decibel Calculations • Example: An amplifier has an input of 3 mV and an output of 5 V. What is the gain in decibels? dB = 20 log 5/0.003 = 20 log 1666.67 = 20 (3.22) = 64.4**Gain, Attenuation,and Decibels**Decibels: Decibel Calculations • Example: A filter has a power input of 50 mW and an output of 2 mW. What is the gain or attenuation? dB = 10 log (2/50) = 10 log (0.04) = 10 (−1.398) = −13.98 • If the decibel figure is positive, that denotes a gain.**Gain, Attenuation,and Decibels**Decibels: Antilogs • The antilog is the number obtained when the base is raised to the logarithm which is the exponent. • Antilogs are used to calculate input or output voltage or power, given the decibel gain or attenuation and the output or input. • The antilog is the base 10 raised to the dB/10 power. • The antilog is readily calculated on a scientific calculator.**Gain, Attenuation,and Decibels**Example: A power amplifier with a 40 dB gain has an output power of 100 W. What is the input power? Solution: dB = 10 log (Pout/ Pin ) antilog = log^(-1) dB/10 = log (Pout/ Pin ) 40/10 = log (Pout/ Pin ) 4 = log (Pout/ Pin ) Antilog 4 = antilog (log (Pout/ Pin ) ) (Pout/ Pin ) =10^ dB/10 (Pout/ Pin ) =10^4 = 10,000 Pin=Pout/10000 = 100/10000 = 0.01 W = 10 mW**Gain, Attenuation,and Decibels**Decibels: dBm and dBc • When a decibel value is computed by comparing a power value to 1 mW, the result is a value called the dBm. This is a useful reference value. • The value dBc is a decibel gain attenuation figure where the reference is the carrier.**Exercises**• 1. What is the gain of an amplifier with an output of 1.5V and an input of 30V? • 2. What is the attenuation of a voltage divider like that in Figure 2.3,where R1 is 3.3K-ohms and R2 is 5.1K-ohms? • 3. What is the overall gain or attenuation of the combination formed by cascading the circuit described in exercises 1 and 2?**Exercises (cont..)**4. The AM receiver radio have three-stages comprised of two amplifiers and one filter with an input power Pin=-10 dBm , and absolute power gains of Ap1 =100, Ap2=0.7 and Ap3=2000. Determine: (i) The dB gain of each stage and the overall gain in dB. (ii) Output power (Po ) in dBm and watts. (iii) What is the difference between a positive and negative decibel (dB)?**Exercises**• 5. Given a four-stage system with an input power of Pin = -15dBm with the absolute power gain of Ap1 = 400, while Ap2 = 2Ap1, Ap4 = 1x10-4Ap2 and Ap3 = 5Ap4.Determine: • the overall gain in dB. • the dB gain of each stage. • the output power in dBm and watt.