Can someone help me with this math problem?

[Darros]

Today in math we had this little assignment, and gave me a bit of trouble. I think I got it right, but I'm really not sure. There was a little issue with factoring, and I'm just wondering what exactly the answer was. I don't have mine back and probably won't for a few days. It's kind of bugging me.

[bobflac]

You know, it has been years since I did Calc, but I could not walk away until I at least tried this.

I got (x+6)(x-1)^2 / x(x-2)^2 but again, I am way too rusty, and I am not too terribly confident in that answer. I can try to show my work if you want.

[Darros]

I think that was similar to what I had, but my denominator was different. I had (x)(x-2)(x^2-3x-2) or something like that. The quadratic there was a headache because it didn't factor and I ended up with huge decimals in my restrictions.

[Integrity]

pain in the ass but hang on lemme get out my paper

that was pretty fun thanks

ANSWER:

(x-1)²(x+1)(x+6)

-----------------------

x(x-2)(x²-3x-2)

EDIT: do you like my perfectly formatted fraction

that was pretty fun thanks

EDIT: oh yeah restrictions

if they want what I think they want:

function is undefined at x = 0, x = 2, and x = 3 +/- sqrt(17) quantity over 2.

simplification is defined but not equal to the original function (f(x) would have been undefined) at x = 1, x = -1

EDIT2: actually after some more thought I suspect "restrictions" only means "when is the original function undefined but the simplification is defined" which would be only x = 1 and x = -1

that's the kind of thing I'd ask my professor on a test though

Edited November 6, 2012 by Mr. Sparkles

[Integrity]

Well, fuck me. Did not realize this wasn't FFtF. I need to start checking ;/

Edited November 6, 2012 by Mr. Sparkles

[Integrity]

legit double-post here

EDIT: which of course comes after a deliberate double-post to make a triple-post :|

Edited November 6, 2012 by Mr. Sparkles

[Grace]

ANSWER:

(x-1)²(x+1)(x+6)

-----------------------

x(x-2)(x²-3x-2)

I did it and arrived to the exact same answer.

Integ pretty much hit the nail on the head with the restrictions as well, so yeah

[Darros]

pain in the ass but hang on lemme get out my paper

that was pretty fun thanks

ANSWER:

(x-1)²(x+1)(x+6)

-----------------------

x(x-2)(x²-3x-2)

EDIT: do you like my perfectly formatted fraction

that was pretty fun thanks

EDIT: oh yeah restrictions

if they want what I think they want:

function is undefined at x = 0, x = 2, and x = 3 +/- sqrt(17) quantity over 2.

simplification is defined but not equal to the original function (f(x) would have been undefined) at x = 1, x = -1

EDIT2: actually after some more thought I suspect "restrictions" only means "when is the original function undefined but the simplification is defined" which would be only x = 1 and x = -1

that's the kind of thing I'd ask my professor on a test though

haha, I could just let you do all my math forever if you want.

Your formatting is beautiful. That's actually great. Thanks.

The restrictions, as we defined them, are any x values, at any point in the whole equation process, that make the denominator equal to 0. So it would be 1, -1, 2, and 0 from the original piece, as well as the 3 +/- root 17 all over 2 restrictions, which had me confused. I thought I factored wrong. It looks like I didn't. Thank you very much.

Also thank you Manix.

Edited November 7, 2012 by Macho Barbarian Darros

[Integrity]

haha, I could just let you do all my math forever if you want.

Your formatting is beautiful. That's actually great. Thanks.

The restrictions, as we defined them, are any x values, at any point in the whole equation process, that make the denominator equal to 0. So it would be 1, -1, 2, and 0 from the original piece, as well as the 3 +/- root 17 all over 2 restrictions, which had me confused. I thought I factored wrong. It looks like I didn't. Thank you very much.

Also thank you Manix.

anytime, dude. I enjoy doing math, and algebra shit like this is good practice to keep me limber for calc.

[nflchamp]

Restrictions for the initial problem are 2, 0, -1, and 1. You get undefineds in the numerator of the overall equation if you put in 2 or 0.