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I find myself in an algebraic loop and can't get out...


Zanarkin
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Its just a matrix with 2 unknowns... I have to find those two unkowns, but i can't figure for the life of me what to do after its reduced...

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Its just a matrix with 2 unknowns... I have to find those two unkowns, but i can't figure for the life of me what to do after its reduced...
It's just a matrix with two U.N. Owens. . . I have to find two U.N. Owens

Sorry I had to. Also Quintessence wins.

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Ok so (i'll just post this here),

X1 - 1/2X2 = h

k + 3h = 0, h = -1/3k

X2 a free variable

This was all taken from the reduced form of the matrix. how do you solve for h and k? Or did i go too far?

Also, I can\t believe i had to read Kalas' post to understand Quin's post :facepalm:

Edited by SlayerX
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Try replacing one of the variables for the equation you need to solve. So, instead of doing k+3h=0 and h=1/3k, you do k + 3(1/3k). if that doesn't work then I'm stumped. Also, lol at you

That would just give me k=0 which means h=0... An answer yes, but i can't help it but feel there is more to this question...

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put your variables on the other side of the equation

then put yourself into OVERMODE

...or you could just turn the universe off and on that usually works

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Ok so (i'll just post this here),

X1 - 1/2X2 = h

k + 3h = 0, h = -1/3k

X2 a free variable

This was all taken from the reduced form of the matrix. how do you solve for h and k? Or did i go too far?

Also, I can\t believe i had to read Kalas' post to understand Quin's post :facepalm:

k + 3h = 0

h = (-1/3)k

then, x1 - (1/2)x2 = (-1/3)k

:/

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Is that the original problem?

No its

3. For what values of h and k is the following system consistent?

2x1 - x2 = h

6x1 + 3x2 = k

Hint: begin by representing the system as a matrix.

Edited by SlayerX
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There are no inconsistencies in this problem, so in theory every solution for h and k qualifies as a consistent answer , if you want an unique one then the condition is that k must be different from 3h. If k is equivalent to 3 h then it will give you infinite solutions, but that is consistent. Do Gauss for the second file and it will not cancel the second equation.

Edit: If you want to have fun solve this problem

3x+6y+9z=6

3x+4y+z=0

2x+4y+6z=A

2x+3y+Bz=1

Find A and B so the system becomes inconsistent, with infinite solutions and with an unique solution.

Hint: consider 5 cases.

Edited by ragnell.
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