Zanarkin Posted October 4, 2012 Share Posted October 4, 2012 AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH! Quote Link to comment Share on other sites More sharing options...
Komeiji Koishi Posted October 4, 2012 Share Posted October 4, 2012 The answer is 42. ALWAYS Quote Link to comment Share on other sites More sharing options...
CT075 Posted October 4, 2012 Share Posted October 4, 2012 Quote Link to comment Share on other sites More sharing options...
Emeraldfox Posted October 4, 2012 Share Posted October 4, 2012 Once you finish your homework you'll get out of the loop. Quote Link to comment Share on other sites More sharing options...
Ring Wraith Posted October 4, 2012 Share Posted October 4, 2012 What is it, a problem within a problem? Go deeper. Quote Link to comment Share on other sites More sharing options...
Hawk King Posted October 4, 2012 Share Posted October 4, 2012 Break your pencil in half. Put the two halves back together. A half plus a half equals a hole. Put the hole on a wall and jump through it. Youre welcome. Quote Link to comment Share on other sites More sharing options...
Zanarkin Posted October 4, 2012 Author Share Posted October 4, 2012 Its just a matrix with 2 unknowns... I have to find those two unkowns, but i can't figure for the life of me what to do after its reduced... Quote Link to comment Share on other sites More sharing options...
Quintessence Posted October 4, 2012 Share Posted October 4, 2012 8b Quote Link to comment Share on other sites More sharing options...
Komeiji Koishi Posted October 4, 2012 Share Posted October 4, 2012 Its just a matrix with 2 unknowns... I have to find those two unkowns, but i can't figure for the life of me what to do after its reduced... It's just a matrix with two U.N. Owens. . . I have to find two U.N. Owens Sorry I had to. Also Quintessence wins. Quote Link to comment Share on other sites More sharing options...
Zanarkin Posted October 4, 2012 Author Share Posted October 4, 2012 (edited) Ok so (i'll just post this here), X1 - 1/2X2 = h k + 3h = 0, h = -1/3k X2 a free variable This was all taken from the reduced form of the matrix. how do you solve for h and k? Or did i go too far? Also, I can\t believe i had to read Kalas' post to understand Quin's post Edited October 4, 2012 by SlayerX Quote Link to comment Share on other sites More sharing options...
Komeiji Koishi Posted October 4, 2012 Share Posted October 4, 2012 Try replacing one of the variables for the equation you need to solve. So, instead of doing k+3h=0 and h=1/3k, you do k + 3(1/3k). if that doesn't work then I'm stumped. Also, lol at you Quote Link to comment Share on other sites More sharing options...
Zanarkin Posted October 4, 2012 Author Share Posted October 4, 2012 Try replacing one of the variables for the equation you need to solve. So, instead of doing k+3h=0 and h=1/3k, you do k + 3(1/3k). if that doesn't work then I'm stumped. Also, lol at you That would just give me k=0 which means h=0... An answer yes, but i can't help it but feel there is more to this question... Quote Link to comment Share on other sites More sharing options...
ragnell. Posted October 4, 2012 Share Posted October 4, 2012 Is that the original problem? Quote Link to comment Share on other sites More sharing options...
Esme Posted October 4, 2012 Share Posted October 4, 2012 put your variables on the other side of the equation then put yourself into OVERMODE ...or you could just turn the universe off and on that usually works Quote Link to comment Share on other sites More sharing options...
Quintessence Posted October 4, 2012 Share Posted October 4, 2012 Ok so (i'll just post this here), X1 - 1/2X2 = h k + 3h = 0, h = -1/3k X2 a free variable This was all taken from the reduced form of the matrix. how do you solve for h and k? Or did i go too far? Also, I can\t believe i had to read Kalas' post to understand Quin's post k + 3h = 0 h = (-1/3)k then, x1 - (1/2)x2 = (-1/3)k :/ Quote Link to comment Share on other sites More sharing options...
Zanarkin Posted October 4, 2012 Author Share Posted October 4, 2012 (edited) Is that the original problem? No its 3. For what values of h and k is the following system consistent? 2x1 - x2 = h 6x1 + 3x2 = k Hint: begin by representing the system as a matrix. Edited October 4, 2012 by SlayerX Quote Link to comment Share on other sites More sharing options...
Zanarkin Posted October 4, 2012 Author Share Posted October 4, 2012 k + 3h = 0 h = (-1/3)k then, x1 - (1/2)x2 = (-1/3)k :/ That doesn't give me a numerical value. Quote Link to comment Share on other sites More sharing options...
Caliban of Sycorax Posted October 4, 2012 Share Posted October 4, 2012 OVER ONE CROSS PRODUCT. THE MOST IMPORTANT THING I EVER LEARNED FROM AP CALCULUS Quote Link to comment Share on other sites More sharing options...
CT075 Posted October 4, 2012 Share Posted October 4, 2012 what if we tried more power Quote Link to comment Share on other sites More sharing options...
Caliban of Sycorax Posted October 4, 2012 Share Posted October 4, 2012 POWER RULE? Quote Link to comment Share on other sites More sharing options...
Esme Posted October 4, 2012 Share Posted October 4, 2012 9 to the THOUSANDTH POWER Quote Link to comment Share on other sites More sharing options...
Komeiji Koishi Posted October 4, 2012 Share Posted October 4, 2012 9 to the THOUSANDTH POWER This Quote Link to comment Share on other sites More sharing options...
ragnell. Posted October 4, 2012 Share Posted October 4, 2012 (edited) There are no inconsistencies in this problem, so in theory every solution for h and k qualifies as a consistent answer , if you want an unique one then the condition is that k must be different from 3h. If k is equivalent to 3 h then it will give you infinite solutions, but that is consistent. Do Gauss for the second file and it will not cancel the second equation. Edit: If you want to have fun solve this problem 3x+6y+9z=6 3x+4y+z=0 2x+4y+6z=A 2x+3y+Bz=1 Find A and B so the system becomes inconsistent, with infinite solutions and with an unique solution. Hint: consider 5 cases. Edited October 4, 2012 by ragnell. Quote Link to comment Share on other sites More sharing options...
Caliban of Sycorax Posted October 4, 2012 Share Posted October 4, 2012 volume of revolutions still scares me. Quote Link to comment Share on other sites More sharing options...
ragnell. Posted October 4, 2012 Share Posted October 4, 2012 1349320302[/url]' post='2145715']volume of revolutions still scares me. they only taught me volume of solids rotating on vertical and horizontal axis, I don't know how to calculate it in a diagonal axis :/ Quote Link to comment Share on other sites More sharing options...
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